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\npython3 using logarithms for finding averages and epsilons
\nSo I am writing a script where I am attempting to find an average with an epsilon. I have found the average on the problem and all that I need to do is check if the average is within epsilon of the desired average and if so, return true and end program. I know that I have to do logarithms to do this but the concept is really pushing my mind to the breaking point, and I can't find how to implement it
\nA:
\nThe idea is to find the difference between the two numbers and then take the exponent to base 10 of that number. So, you will need to convert both to the same type, which is an integer, for this method to work properly. If you use the built-in function round() to round your numbers, this should work without any if/else:\ndef find_epsilon( a, b, epsilon ):\n diff = abs( a - b )\n base = 10\n exponent = math.floor( math.log10( diff / epsilon ) )\n return base**exponent * epsilon
\n for a, b in [(2.0, 2.0), (0.0, 1.0), (0.75, 0.75), (0.0, 0.0), (2.0, 3.0)]:\n print( find_epsilon( a, b, 0\n https://documenter.getpostman.com/view/21828756/Uzs5W4TT https://documenter.getpostman.com/view/21901015/Uzs5W4TU https://documenter.getpostman.com/view/21828265/Uzs5W4TR https://documenter.getpostman.com/view/21855573/Uzs5W4TV https://documenter.getpostman.com/view/21852923/Uzs5W4TS # Introduction\nWhat does your API do?
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