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\nHow to ignore typedefs and some template parameters in template specialization
\nI have an abstract template:\ntemplate\nstruct MyClass {\n virtual void func(int i) = 0;\n };
\nI would like to add new functions like this:\ntemplate\nstruct MyClass {\n void func(int i, double z) {\n // code\n }\n };\n \n But it does not work. How can I do this?\n \n A:\n \n You cannot, since MyClass is a dependent name, meaning there is no way to define function typedefs of MyClass in the specialization. For example, this is illegal:\n template\n struct MyClass {\n typedef void MyClass::func(int i);\n //...\n };\n \n because the MyClass part of the name of the type should be a class template name. The only way to do that is to explicitly specialize the type:\n template\n struct MyClass : public MyClass {\n //...\n };\n https://documenter.getpostman.com/view/21890026/UzkcSYco https://documenter.getpostman.com/view/21840751/UzkcSYYV https://documenter.getpostman.com/view/21903041/UzkcSYcq https://documenter.getpostman.com/view/21852829/UzkcSYYX https://documenter.getpostman.com/view/21882755/UzkcSYYY # Introduction\nWhat does your API do?
\nThings that the developers should know about
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