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\nHow to prove that a graph is a tournament graph?
\nLet G be a simple undirected graph. Suppose that for all $u$ and $v$ we have $|uN(v)|\\le |N(u)\\cap N(v)|$. Prove that G is a tournament graph. (A tournament graph is a graph such that if we choose any two vertices, one of them has a strictly smaller distance to the other one than the distance in the other case.)
\nA:
\nI might have some of the details wrong, but I will give it a try.\nObserve that $|uN(v)| = |(uN(v)\\cap N(u))\\cup (N(v)\\cap uN(u))|\\le |N(v)\\cap N(u)|+|(N(u)\\cap N(v))\\cup (uN(u)\\cap vN(v))|\\le |N(v)\\cap N(u)|+|N(u)\\cap N(v)| = |N(v)| \\le |N(u)| + |N(v)| = |N(u)\\cup N(v)| = |N(u)|+|N(v)|-1 = |N(u)|+|N(v)|\n7582aa13b2
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