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As the Discussions Forum is very popular, it has a low loading time. The source is from a third party that could be modified. The source of the feed is directly linked to it.Q:

Allocating memory for allocating memory?

Is there a name for a situation where a variable is used to allocate memory for itself?\nFor example:\nchar* a = malloc(sizeof(char*));

char* b = malloc(sizeof(char*));

*a = *b;

Can the above code be optimised to the following?\nchar a[1];\nchar b[1];\n*a = *b;

In your scenario the obvious name would be undefined behavior.\nFor your example the variable b is no longer a pointer.\nTry\n(*a) = b;

and this will only work for arrays of size 1.

It's not a very good example.\nA more real-world example would be:\ntypedef struct element* Element;

int i;\nElement *a = malloc(sizeof(Element));\nElement *b = malloc(sizeof(Element));

*a = *b;\na->data = b->data;

If you read this as, \"I've got two struct elements, so I allocate memory for struct elements\", then you can't do what you want.\nIt is perfectly fine to write:\nElement *a = malloc(sizeof(Element[2]));

Or:\nElement a[2];

If you read it as, \"Here's a bunch of struct elements\", then you can use it, no problem.

The reason this code is legal is that C implicitly promotes malloc-ed variables to pointers. So in your example:

a is promoted to a pointer to a char, so it has type char (*)[1];\nb is promoted to a pointer to a char, so it has type char *;\nthe second declaration dereferences the pointer and casts it to char, and then assigns the value.

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