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\nHow to factor an expression containing inversion?
\nI have an expression like this\n$$\\lim_{n\\to \\infty} \\frac{\\sum_{k=0}^{n-1} k^2}{\\sum_{k=0}^{n-1} k} = \\frac{n(n+1)}{2n(n+1)} = \\frac{2}{2}$$\nI should factor out the $1/2$, and $\\frac{1}{2}$ appears. \nI have tried to solve it by \n$(a+b)^2 = a^2+b^2+2ab$\nHowever, I don't know how to continue. I can see the signs come out but I couldn't get the coefficients.
\nA:
\nIt is indeed correct that $$(a+b)^2=(a^2+2ab)+b^2$$\nand therefore,\n$$\n\\begin{align}\n(a+b)^2&=a^2+b^2+2ab\\\n&=a^2+b^2+2ab\\\n&=a^2+b^2+2ab\\tag{1}\\\n&=(a+b)^2\\tag{2}\n\\end{align}\n$$\nbut I would be careful about using $(2)$ in this problem. If we already know the identity $(1)$ then there is no reason to evaluate $(2)$ as well.\nAnother way to see this is to note that the identity\n$$\n(a+b)^2=(a^2+2ab)+b^2\n$$\nalso allows us to factor out $a^2+b^2$ from the LHS of this identity.
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